(x+2)(2x^2-3x+5)=

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Solution for (x+2)(2x^2-3x+5)= equation: 


Simplifying
(x + 2)(2x2 + -3x + 5) = 0

Reorder the terms:
(2 + x)(2x2 + -3x + 5) = 0

Reorder the terms:
(2 + x)(5 + -3x + 2x2) = 0

Multiply (2 + x) * (5 + -3x + 2x2)
(2(5 + -3x + 2x2) + x(5 + -3x + 2x2)) = 0
((5 * 2 + -3x * 2 + 2x2 * 2) + x(5 + -3x + 2x2)) = 0
((10 + -6x + 4x2) + x(5 + -3x + 2x2)) = 0
(10 + -6x + 4x2 + (5 * x + -3x * x + 2x2 * x)) = 0
(10 + -6x + 4x2 + (5x + -3x2 + 2x3)) = 0

Reorder the terms:
(10 + -6x + 5x + 4x2 + -3x2 + 2x3) = 0

Combine like terms: -6x + 5x = -1x
(10 + -1x + 4x2 + -3x2 + 2x3) = 0

Combine like terms: 4x2 + -3x2 = 1x2
(10 + -1x + 1x2 + 2x3) = 0

Solving
10 + -1x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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